Pipes and Cisterns Questions & Answers PDF

By | April 20, 2021
Pipes and Cisterns Problems with Solutions

Problems based on pipes and cistern questions are common topics that are asked in quantitative aptitude sections. We are providing pipes and cisterns questions and answers basics ​examples with shortcut tricks.

Pipes and cisterns problems are another type of time and work problems. If you are perfect with the time & work Problems, then you can easily solve these problems and score well in exams.

Pipes and cisterns formulas with a detailed description and explanation will help you to solve the topic.

Pipe and Cistern Solved Questions

These Pipes and cisterns tricks will cover all pipe and cistern topics. Aptitude questions and answers section on Pipes and Cisterns with questions and answers are helpful for various interview, competitive examinations, and entrance tests.

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Pipes and Cisterns Formulas

  • If x hours are required to fill up a tank, then part filled in 1 hr =1/x.
  • When y hours are required to empty the tank, then part emptied in 1 hour = 1/y.
  • If a pipe can fill a tank in x hours and can empty the same tank in y hours. When both the pipes are opened at the same time, then the net part of the tank filled in 1 hr = {(xy) / (y-x)}, provided y>x.
  • While a pipe can fill a tank in x hours and can empty the same tank in y hours. When both the pipes are opened at the same time, then the net part of the tank filled in 1 hr = {(xy) / (x-y)}, provided x>y.
  • Net work done = (Sum of work done by Inlets) – (Sum of work done by Outlets).
  • One inlet can fill the tank in x hr and the other inlet can fill the same tank in y hrs, if both the inlets are opened at the same time, the time taken to fill the whole tank = {(xy) / (y+x)}.
  • If two pipes take x and y hours respectively to fill a tank of water and a third pipe is opened which takes z hours to empty the tank, then the time taken to fill the tank = {1 / (1/x)+(1/y)+(1/z)} and the net part of the tank filled in 1 hr = (1/x)+(1/y)-(1/z).

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